document.write( "Question 59935: 18. Solve\r
\n" ); document.write( "\n" ); document.write( "(rs)x-1=x-3\r
\n" ); document.write( "\n" ); document.write( "I have no idea on how to solve this problem and my head is beginning to hurt. Can someone help me please.
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Algebra.Com's Answer #41131 by chitra(359)\"\" \"About 
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The given expression is: \r
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\n" ); document.write( "\n" ); document.write( "rs(x - 1) = x - 3\r
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\n" ); document.write( "\n" ); document.write( "We remove the radical on the left hand side by squaring both sides of the given expression.\r
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\n" ); document.write( "\n" ); document.write( "That is:\r
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\n" ); document.write( "\n" ); document.write( "(x - 1) = (x - 3)^2 \r
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\n" ); document.write( "\n" ); document.write( "Expanding the right hand side by using the formula (a - b)^2, we get:\r
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\n" ); document.write( "\n" ); document.write( "(x - 1) = x^2 - 6x + 9 \r
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\n" ); document.write( "\n" ); document.write( "Adding 1 - x to both sides of the above equation, we get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 6x + 9 + 1 - x = 0 \r
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\n" ); document.write( "\n" ); document.write( "x^2 - 7x + 10 = 0 [Adding the like terms, we get]\r
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\n" ); document.write( "\n" ); document.write( "Using the method of Factorization, we get: \r
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\n" ); document.write( "\n" ); document.write( "x^2 - 5x - 2x + 10 = 0 \r
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\n" ); document.write( "\n" ); document.write( "x(x - 5) - 2(x - 5) = 0\r
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\n" ); document.write( "\n" ); document.write( "(x - 2)(x - 5) = 0 \r
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\n" ); document.write( "\n" ); document.write( "Thus, the values of x are 2 and 5.\r
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