document.write( "Question 59923This question is from textbook Elementry and Intermediate algebra
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document.write( ": I need a bit of help on this one....\r
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document.write( "It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together? \n" );
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Algebra.Com's Answer #41128 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! It usually takes Eva 3 hours longer to do the monthly payroll than it takes Cindy. They start working on it together at 9.00 AM and at 5.00 PM they have 90% of it done. If Eva took s 2 hour lunch break while Cindy had none, then how much longer will it take for them to finish the payroll working together? \n" ); document.write( "------------ \n" ); document.write( "Cindy DATA: \n" ); document.write( "Time = x hrs./job ; Rate = 1/x job/hr. \n" ); document.write( "------------- \n" ); document.write( "Eva DATA: \n" ); document.write( "Time = x+3 hrs/job ; Rate = 1/(x+3) job/hr. \n" ); document.write( "-------------- \n" ); document.write( "Together DATA: \n" ); document.write( "Rate = 1/x + 1/(x+3) = (2x+3)/(x^2+3x) job/hr\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( "Cindy worked 8 hrs. \n" ); document.write( "Eva worked 6 hours. \n" ); document.write( "8*(cindy rate) + 6(eva rate)= 0.9 job \n" ); document.write( "8/x + 6/(x+3) = 9/10 \n" ); document.write( "8(x+3)10 + 6x(10)=9x(x+3) \n" ); document.write( "80x+240+60x = 9x^2+27x \n" ); document.write( "9x^2-113x-240=0 \n" ); document.write( "x=[113+-sqrt(113^2-4*9*-240]/18 \n" ); document.write( "x=[113+-sqrt21409]/18 \n" ); document.write( "x=[113+146,3181]/18 \n" ); document.write( "x=14.41 hrs \n" ); document.write( "--------------- \n" ); document.write( "If x = 14.41 the \"working together rate\" is \n" ); document.write( "(2x+3)/(x^2+3x) job/hr = (31.81)/(14.41^2+3(14.41))=31.81/250.88 job/hr \n" ); document.write( "EQUATION: \n" ); document.write( "Let z be the number of hours required to \"finish the job\" \n" ); document.write( "(finish the job means do 0.1 of it). \n" ); document.write( "So, (31.81/250.88) z = 0.1 \n" ); document.write( "z=0.788 hr \n" ); document.write( "z=0.788(60)=47.32 minutes (time required for them to finish the job together) \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |