document.write( "Question 59826: solve for x\r
\n" ); document.write( "\n" ); document.write( "1/4x-2=1/2x-3
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Algebra.Com's Answer #41125 by jaimehot(1)\"\" \"About 
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1/4x-2=1/2x-3\r
\n" ); document.write( "\n" ); document.write( "first add 3 to both sides of the equation
\n" ); document.write( "1/4x-2 + 3 =1/2x-3 + 3\r
\n" ); document.write( "\n" ); document.write( "you get
\n" ); document.write( "1/4x + 1 = 1/2x\r
\n" ); document.write( "\n" ); document.write( "now subtract 1/4x to both sides of the equation
\n" ); document.write( "1/4x - 1/4x + 1 = 1/2x - 1/4x
\n" ); document.write( "or
\n" ); document.write( "1 = 1/2x - 1/4x\r
\n" ); document.write( "\n" ); document.write( "but we know that
\n" ); document.write( "1/2x = 2/4x\r
\n" ); document.write( "\n" ); document.write( "substitute in previous equqtion and you have
\n" ); document.write( "1 = 2/4x -1/4x
\n" ); document.write( "or
\n" ); document.write( "1 = 1/4x\r
\n" ); document.write( "\n" ); document.write( "multiply both sides times 4 and\r
\n" ); document.write( "\n" ); document.write( "4 = x\r
\n" ); document.write( "\n" ); document.write( "so
\n" ); document.write( "x=4\r
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