document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=660536>Question 660536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle's measure is 12 degree more than 1/2 the measure of its supplement. Find the measure of the angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411240 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an angle's measure is 12 degree more than 1/2 the measure of its supplement. Find the measure of the angle?<BR>\n" );
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document.write( "Angle: x<BR>\n" );
document.write( "Supplement: 180-x<BR>\n" );
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document.write( "x = (1/2)(180-x) + 12<BR>\n" );
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document.write( "x = 90 - (x/2) + 12<BR>\n" );
document.write( "(3/2)x = 102<BR>\n" );
document.write( "x = (2/3)102 = 2*34 = 68 degrees<BR>\n" );
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document.write( "180-x = 180-68 = 112 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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