document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=660536>Question 660536</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angle's measure is 12 degree more than 1/2 the measure of its supplement. Find the measure of the angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411238 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = angle <BR>\n" );
document.write( "y = angle's supplement\r<BR>\n" );
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document.write( "x + y = 180<BR>\n" );
document.write( "x = 12 + 1/2y\r<BR>\n" );
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document.write( "Substitute the second into the first equation<BR>\n" );
document.write( "(12 + 1/2y) + y = 180<BR>\n" );
document.write( "12 + 1 1/2y = 180<BR>\n" );
document.write( "12 - 12 + 1 1/2y = 180 - 12<BR>\n" );
document.write( "1 1/2y = 168<BR>\n" );
document.write( "1 1/2 = 3/2<BR>\n" );
document.write( "(3/2y)/3/2 = 168/(3/2)<BR>\n" );
document.write( "y = 168(2/3)<BR>\n" );
document.write( "y = 112\r<BR>\n" );
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document.write( "x = 180 - 112 = 68 is the measure of the angle </SPAN>\n" );
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