document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=660475>Question 660475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 feet more than twice the width. the area is 90 square feet. what are the dimensions of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411228 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a = lw<BR>\n" );
document.write( "Equations<BR>\n" );
document.write( "l = 3 + 2w<BR>\n" );
document.write( "90 = lw\r<BR>\n" );
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document.write( "Substitute the first into the second equation<BR>\n" );
document.write( "90 = (3+2w)w<BR>\n" );
document.write( "90 = 3w + 2w^2<BR>\n" );
document.write( "2w^2 + 3w - 90 = 0<BR>\n" );
document.write( "Multiples of 90: 30,3; 45,2; 18,5; 6,15<BR>\n" );
document.write( "Looking for combination where 2 x one of the pair will subtract from the other to yield 3<BR>\n" );
document.write( "(2w + 15)(w - 6)  Mixed signs due to - 90<BR>\n" );
document.write( "2w + 15 = 0; w = -15/2  NO<BR>\n" );
document.write( "w - 6 = 0; w = 6\r<BR>\n" );
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document.write( "width = 6<BR>\n" );
document.write( "length = 3 + 2(6) = 15 </SPAN>\n" );
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