document.write( "Question 660443: the area of a square is numerically 117 more than the perimeter. Find the length of the side. \n" ); document.write( "
Algebra.Com's Answer #411222 by kevwill(135)\"\" \"About 
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Let s be the length of a side of the square. Then the perimeter of the square is \"4%2As\" and the area is \"s%5E2\"
\n" ); document.write( "\"s%5E2+=+4s+%2B+117\"
\n" ); document.write( "\"s%5E2+-+4s+-+117+=+0\"
\n" ); document.write( "Factoring this equation gives
\n" ); document.write( "\"%28s+-+13%29%28s+%2B+9%29+=+0\"
\n" ); document.write( "So we have s = 13 or s = -9. Since the side of a square cannot have negative length, the side must be 13. The perimeter would be 52 and the area would be 169.
\n" ); document.write( "You could also use the quadratic equation \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" to solve for s, with a=1, b=-4 and c=-117. \r
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