document.write( "Question 660417: find three consecutive integers whose sum is 11 more than twice the greatest of the three integers. \n" ); document.write( "
Algebra.Com's Answer #411181 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! Set the equation \n" ); document.write( "x + x+1 x+2 = 11 + 2(x+2) \n" ); document.write( "Combine like terms and distribute the 2 on the right \n" ); document.write( "3x + 3 = 11 + 2x + 4 \n" ); document.write( "3x - 2x + 3 - 3 = 11 + 2x - 2x + 4 - 3 \n" ); document.write( "x = 11 + 4 - 3 \n" ); document.write( "x = 12 \n" ); document.write( "Integers are 12, 13 and 14 \n" ); document.write( "Proof \n" ); document.write( "12 + 13 + 14 = 39 \n" ); document.write( "11 + 2(12+2) = 11 + 2(14) = 11 + 28 = 39 \n" ); document.write( " \n" ); document.write( " |