document.write( "Question 660417: find three consecutive integers whose sum is 11 more than twice the greatest of the three integers. \n" ); document.write( "
Algebra.Com's Answer #411181 by ReadingBoosters(3246)\"\" \"About 
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Set the equation
\n" ); document.write( "x + x+1 x+2 = 11 + 2(x+2)
\n" ); document.write( "Combine like terms and distribute the 2 on the right
\n" ); document.write( "3x + 3 = 11 + 2x + 4
\n" ); document.write( "3x - 2x + 3 - 3 = 11 + 2x - 2x + 4 - 3
\n" ); document.write( "x = 11 + 4 - 3
\n" ); document.write( "x = 12
\n" ); document.write( "Integers are 12, 13 and 14
\n" ); document.write( "Proof
\n" ); document.write( "12 + 13 + 14 = 39
\n" ); document.write( "11 + 2(12+2) = 11 + 2(14) = 11 + 28 = 39
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