document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=660419>Question 660419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> jack was 11 years older that priscilla. Together their ages totaled 153. What were their ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411177 by </B><A HREF=/tutors/aboutme.mpl?userid=lenny460><B>lenny460(1073)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lenny460><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lenny460><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> jack was 11 years older that priscilla. Together their ages totaled 153. What were their ages?\r<BR>\n" );
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document.write( "Let the age of Jack be n + 11\r<BR>\n" );
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document.write( "Let the age of Priscilla be n\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "n + 11 + n = 153\r<BR>\n" );
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document.write( "Combine like terms:\r<BR>\n" );
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document.write( "n + n = 2n\r<BR>\n" );
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document.write( "2n + 11 = 153\r<BR>\n" );
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document.write( "Subtract 11 from each side of the equation.\r<BR>\n" );
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document.write( "2n + 11 - 11 = 153 - 11\r<BR>\n" );
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document.write( "Combine like terms:\r<BR>\n" );
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document.write( "11 - 11 = 0\r<BR>\n" );
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document.write( "153 - 11 = 142\r<BR>\n" );
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document.write( "2n = 142\r<BR>\n" );
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document.write( "Divide each side by 2\r<BR>\n" );
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document.write( "2n/2 = 142/2\r<BR>\n" );
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document.write( "n = 71\r<BR>\n" );
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document.write( "n + 11 = 71 + 11 = 82\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "Priscilla is 71 years old and\r<BR>\n" );
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document.write( "Jack is 82 years old\r<BR>\n" );
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document.write( "Lennox Obuong<BR>\n" );
document.write( "Algebra 2 Student<BR>\n" );
document.write( "Email: obuong3@aol.com </SPAN>\n" );
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