document.write( "Question 660356: I am having some issues with logarithm equations and need some help.\r
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document.write( "first problem: 2 log(z)-log(z2+4z+1)=0 The 2 after the z here is z squared but I can't get a little 2 on my pc.\r
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document.write( "next problem: 2e3y+8 - 11e5-10y = 0 here the 3y+8 is to the power and small again and so is the 5-10y but i can't get it on my pc.\r
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document.write( "next problem: 1-8In {_2x-1___} = 14 That is 2x - 1 over 7
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document.write( "I am an a student usually, but we changed math teachers 3 x so far this year and this is causing issues with learniing. This is hwork. We had 30 problems. I did what I could and am stumped on about 5 or 6 of them. Here are 3...If i can get these, I can probably figure out the others. I have been up all nite with this and just went to bed and will be getting up at 5 to finish, so if anyone up, I would really appreciate the help. Thank you much.\r
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document.write( "Bob \n" );
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Algebra.Com's Answer #411157 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! first problem: 2 log(z)-log(z2+4z+1)=0 The 2 after the z here is z squared but I can't get a little 2 on my pc. \n" ); document.write( "2 log(z)-log(z2+4z+1)=0 \n" ); document.write( "log(z^2)=log(z^2+4z+1) \n" ); document.write( "z^2=z^2+4z+1 \n" ); document.write( "4z+1=0 \n" ); document.write( "z=-1/4 \n" ); document.write( "no solution: z>0 \n" ); document.write( ".. \n" ); document.write( "next problem: 2e3y+8 - 11e5-10y = 0 here the 3y+8 is to the power and small again and so is the 5-10y but i can't get it on my pc. \n" ); document.write( "2e^(3y+8) - 11e^(5-10y) = 0 \n" ); document.write( "2e^(3y+8) = 11e^(5-10y) \n" ); document.write( "take log of both sides \n" ); document.write( "ln2+(3y+8)lne=ln11+(5-10y)lne \n" ); document.write( "lne=1 \n" ); document.write( "ln2+3y+8=ln11+5-10y \n" ); document.write( "3y+8-5+10y=ln11-ln2 \n" ); document.write( "13y+3=(ln11-ln2) \n" ); document.write( "y=((ln11-ln2-3)/13≈-.0996 \n" ); document.write( ".. \n" ); document.write( "next problem: 1-8In {_2x-1___} = 14 That is 2x - 1 over 7 \n" ); document.write( "1-8ln[(2x-1)/7]=14 (I hope I got this right) \n" ); document.write( "-8ln[(2x-1)/7]=13 \n" ); document.write( "ln[(2x-1)/7]=-13/8 \n" ); document.write( "convert to exponential form: \n" ); document.write( "e^(-13/8)=(2x-1)/7 \n" ); document.write( "using calculator: \n" ); document.write( ".1969=(2x-1)/7 \n" ); document.write( "2x-1=.1969*7=1.3783 \n" ); document.write( "2x=2.3783 \n" ); document.write( "x=2.3783/2=1.1892 \n" ); document.write( "note: answers are rounded to four decimal places \n" ); document.write( " |