document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659764>Question 659764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 5 times a integer is subtracted from twice the square of the integer, the result is 63. Find the integer  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411134 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = integer<BR>\n" );
document.write( "2x^2-5x=63<BR>\n" );
document.write( "2x^2 - 5x - 63 = 0<BR>\n" );
document.write( "(   +   )(   -  )  Mixed sign as the - 63<BR>\n" );
document.write( "multiples of 63: 3,21; 7,9; 63,1<BR>\n" );
document.write( "Thinking 2 times one of these multiples, minus the other member of the pair needs to give 5, I use 7,9.  <BR>\n" );
document.write( "Where 2x7=14-9=5  <BR>\n" );
document.write( "Since the 5 is negative, apply the minus to the 7.<BR>\n" );
document.write( "(2x + 9)(x - 7)\r<BR>\n" );
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document.write( "x - 7 = 0<BR>\n" );
document.write( "x=7  OK<BR>\n" );
document.write( "2x+9=0<BR>\n" );
document.write( "2x=-9<BR>\n" );
document.write( "x=-9/2 NO\r<BR>\n" );
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document.write( "The integer is 7 </SPAN>\n" );
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