document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659587>Question 659587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that the sum of the smallest and largest is eleven less than three times the middle integer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #411124 by </B><A HREF=/tutors/aboutme.mpl?userid=kevwill><B>kevwill(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kevwill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kevwill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=411124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+2, and x+4 be the three consecutive odd integers.  Then:<BR>\n" );
document.write( "x + (x+4) = 3*(x+2) - 11<BR>\n" );
document.write( "2x + 4 = 3x + 6 - 11<BR>\n" );
document.write( "2x + 4 = 3x - 5<BR>\n" );
document.write( "Subtracting 2x-5 from both sides:<BR>\n" );
document.write( "2x + 4 - (2x - 5) = 3x - 5 - (2x - 5)<BR>\n" );
document.write( "2x + 4 - 2x + 5 = 3x - 5 - 2x + 5<BR>\n" );
document.write( "9 = x<BR>\n" );
document.write( "So the three consecutive odd integers are 9, 11, and 13.<BR>\n" );
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