document.write( "Question 660214: two fractions have denominators 3 and 4. Their sum is 17/12. If the numerators are switched, the sum is 3/2. Determine the two numerators.
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Algebra.Com's Answer #411082 by josmiceli(19441)\"\" \"About 
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(1) \"+x%2F3+%2B+y%2F4+=+17%2F12+\"
\n" ); document.write( "(2) \"+y%2F3+%2B+x%2F4+=+3%2F2+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+4x+%2B+3y+=+17+\"
\n" ); document.write( "(2) \"+4y+%2B+3x+=+18+\"
\n" ); document.write( "-------------------
\n" ); document.write( "(1) \"+4x+%2B+3y+=+17+\"
\n" ); document.write( "(2) \"+3x+%2B+4y+=+18+\"
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\n" ); document.write( "Multiply both sides of (1) by \"+3+\"
\n" ); document.write( "Multiply both sides of (2) by \"+4+\"
\n" ); document.write( "------------------
\n" ); document.write( "(1) \"+12x+%2B+9y+=+51+\"
\n" ); document.write( "(2) \"+12x+%2B+16y+=+72+\"
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\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+12x+%2B+16y+=+72+\"
\n" ); document.write( "(1) \"+-12x+-+9y+=+-51+\"
\n" ); document.write( "\"+7y+=+21+\"
\n" ); document.write( "\"+y+=+3+\"
\n" ); document.write( "---------
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+4x+%2B+3%2A3+=+17+\"
\n" ); document.write( "(1) \"+4x+=+17+-+9+\"
\n" ); document.write( "(1) \"+4x+=+8+\"
\n" ); document.write( "(1) \"+x+=+2+\"
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\n" ); document.write( "The numerators are 2 and 3
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+x%2F3+%2B+y%2F4+=+17%2F12+\"
\n" ); document.write( "(1) \"+2%2F3+%2B+3%2F4+=+17%2F12+\"
\n" ); document.write( "(1) \"+8%2F12+%2B+9%2F12+=+17%2F12+\"
\n" ); document.write( "(1) \"+17%2F12+=+17%2F12+\"\r
\n" ); document.write( "\n" ); document.write( "(2) \"+y%2F3+%2B+x%2F4+=+3%2F2+\"
\n" ); document.write( "(2) \"+3%2F3+%2B+2%2F4+=+3%2F2+\"
\n" ); document.write( "(2) \"+1+%2B+1%2F2+=+3%2F2+\"
\n" ); document.write( "(2) \"+3%2F2++=+3%2F2+\"
\n" ); document.write( "OK\r
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