document.write( "Question 660214: two fractions have denominators 3 and 4. Their sum is 17/12. If the numerators are switched, the sum is 3/2. Determine the two numerators.
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Algebra.Com's Answer #411082 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! (1) \n" ); document.write( "(2) \n" ); document.write( "----------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "------------------- \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "Multiply both sides of (2) by \n" ); document.write( "------------------ \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "-------------------- \n" ); document.write( "Subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------- \n" ); document.write( "and, since \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------ \n" ); document.write( "The numerators are 2 and 3 \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "\n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |