document.write( "Question 660160: Jack invests $1500 at a certain annual interest rate, and he invests another $2000 at an annual rate that is one-half percent higher. If he receives a total of $255 interest in 1 year, at what rate is the $1500 invested?
\n" ); document.write( "I've tried the r= interest/Pt and it didn't work. Im not sure what to do with the 2000 at an annual rate that is on half percent higher
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Algebra.Com's Answer #411072 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+r+\" = rate that $1500 is invested at
\n" ); document.write( "\"+r+%2B+.005+\" = rate that $2000 is invested at
\n" ); document.write( "given:
\n" ); document.write( "\"+1500r+%2B+2000%2A%28+r+%2B+.005+%29+=+255+\"
\n" ); document.write( "\"+1500r+%2B+2000r+%2B+10+=+255+\"
\n" ); document.write( "\"+3500r+=+245+\"
\n" ); document.write( "\"+r+=+245+%2F+3500+\"
\n" ); document.write( "\"+r+=+.07+\"
\n" ); document.write( "$1500 is invested at 7%
\n" ); document.write( "check:
\n" ); document.write( "\"+1500r+%2B+2000%2A%28+r+%2B+.005+%29+=+255+\"
\n" ); document.write( "\"+1500%2A.07+%2B+2000%2A.075+=+255+\"
\n" ); document.write( "\"+105+%2B+150+=+255+\"
\n" ); document.write( "\"+255+=+255+\"
\n" ); document.write( "OK
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