document.write( "Question 59881This question is from textbook College Algebra
\n" ); document.write( ": Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.\r
\n" ); document.write( "\n" ); document.write( "2x^2=48\r
\n" ); document.write( "\n" ); document.write( "1) 2x^2/2=48/2
\n" ); document.write( "2) x^2=24
\n" ); document.write( "3) x=+-sq root 24
\n" ); document.write( "4) ????
\n" ); document.write( "

Algebra.Com's Answer #41105 by funmath(2933)\"\" \"About 
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Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.\r
\n" ); document.write( "\n" ); document.write( "2x^2=48\r
\n" ); document.write( "\n" ); document.write( "1) 2x^2/2=48/2
\n" ); document.write( "2) x^2=24
\n" ); document.write( "3) x=+-sq root 24
\n" ); document.write( "4) ????
\n" ); document.write( "I am assuming, that you need this reduced and not an approximate answer that you can get with a calculator. Separate 24 into factors in which one is a perfect square.
\n" ); document.write( "\"x=-sqrt%2824%29\" and \"x=sqrt%2824%29\"
\n" ); document.write( "\"x=-sqrt%284%29%2Asqrt%286%29\" and \"x=sqrt%284%29%2Asqrt%286%29\"
\n" ); document.write( "The square root of 4 is 2.
\n" ); document.write( "\"x=-2%2Asqrt%286%29\" and \"x=2%2Asqrt%286%29\"
\n" ); document.write( "Happy Calculating!!!
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