document.write( "Question 660110: 2x+4y=3 1/2 if (x, 2 3/4) what is the value of x \n" ); document.write( "
Algebra.Com's Answer #411042 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! 2x+4y=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+4(2+3/4)=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+4(8/4+3/4)=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+4(11/4)=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+44/4=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x+11=3 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x=3 -11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x=-8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=-8/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the ordered pair is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( "-------------------------------------------------------------------------------------------------------------- \n" ); document.write( " |