document.write( "Question 660051: The second of two numbers is 6 less than the first. Twice the sum of the first number and 1 is the same as 9 times the second. Find the numbers.\r
\n" ); document.write( "\n" ); document.write( "i tried to start the equation and this is what i got but im still not sure:
\n" ); document.write( "2(x+1)+x-6=9(x-6)\r
\n" ); document.write( "\n" ); document.write( "please help!!!
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Algebra.Com's Answer #411032 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
It should be \r
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\n" ); document.write( "\n" ); document.write( "2(x+1)+x-6=9(x-6) \r
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\n" ); document.write( "\n" ); document.write( "Notice the change in red\r
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\n" ); document.write( "\n" ); document.write( "In a much cleaner look, the equation should be this\r
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\n" ); document.write( "\n" ); document.write( "2(x+1) = 9(x-6)\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%2B1%29=9%28x-6%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B2=9x-54\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=9x-54-2\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-9x=-54-2\" Subtract \"9x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-7x=-54-2\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-7x=-56\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-56%29%2F%28-7%29\" Divide both sides by \"-7\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=8\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=8\" \r
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\n" ); document.write( "\n" ); document.write( "This means that the first number is 8 and the second number is 2 (since x-6 = 8-6 = 2)\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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\n" ); document.write( "\n" ); document.write( "Jim
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