document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59881>Question 59881</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/061838670X/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Use square root procedure to solve the following quadratic equation.  I was able to get down to the last part of problem but have been stumped since.\r<BR>\n" );
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document.write( "2x^2=48\r<BR>\n" );
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document.write( "1) 2x^2/2=48/2<BR>\n" );
document.write( "2) x^2=24<BR>\n" );
document.write( "3) x=+-sq root 24<BR>\n" );
document.write( "4) ???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41103 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X^2=48<BR>\n" );
document.write( "X^2=48/2<BR>\n" );
document.write( "X^2=24<BR>\n" );
document.write( "X=+-SQRT24<BR>\n" );
document.write( "X=+-2SQRT6 OR<BR>\n" );
document.write( "X=+-2*2.4494897 OR<BR>\n" );
document.write( "X=+-4.8989794 </SPAN>\n" );
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