document.write( "Question 660034: |2x-3| +1 =4x \n" ); document.write( "
Algebra.Com's Answer #411025 by lwsshak3(11628)\"\" \"About 
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|2x-3| +1 =4x
\n" ); document.write( "solve for x under 2 possibilities
\n" ); document.write( "(2x-3) +1 =4x
\n" ); document.write( "2x-3 +1 =4x
\n" ); document.write( "2x=-2
\n" ); document.write( "x=-2/2=-1
\n" ); document.write( "check:
\n" ); document.write( "|2x-3| +1
\n" ); document.write( "=|4/3-9/3| +1
\n" ); document.write( "=|-5/3| +1
\n" ); document.write( "=5/3+1
\n" ); document.write( "=8/3≠4
\n" ); document.write( "Therefore, reject solution: x=-1
\n" ); document.write( "..
\n" ); document.write( "-(2x-3) +1 =4x
\n" ); document.write( "-2x+3 +1 =4x
\n" ); document.write( "6x=4
\n" ); document.write( "x=4/6=2/3
\n" ); document.write( "check:
\n" ); document.write( "|2x-3| +1=|4/3-9/3| +1=|-5/3| +1=5/3+3/3=8/3
\n" ); document.write( "4x=4*2/3=8/3
\n" ); document.write( "left side=right side
\n" ); document.write( "solution of x=2/3 ok \n" ); document.write( "
\n" );