document.write( "Question 659911: can someone explain how do i find the distance between this points:\r
\n" ); document.write( "\n" ); document.write( "A=(6-1)B=(1,11)\r
\n" ); document.write( "\n" ); document.write( "A=(-3,-5)B=(3,-13)\r
\n" ); document.write( "\n" ); document.write( "A=(2,-2)B(-2,2)\r
\n" ); document.write( "\n" ); document.write( "A=(4,-6)B=(-2,4)
\n" ); document.write( "

Algebra.Com's Answer #410977 by Alan3354(69443)\"\" \"About 
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can someone explain how do i find the distance between this points:\r
\n" ); document.write( "\n" ); document.write( "A=(6,-1)B=(1,11)
\n" ); document.write( "diffy = -1 - 11 = -12
\n" ); document.write( "diffx = 6 - 1 = 5
\n" ); document.write( "----
\n" ); document.write( "\"distance+=+sqrt%28diffy%5E2+%2B+diffx%5E2%29+=+sqrt%28144+%2B+25%29\"
\n" ); document.write( "distance = 13 units
\n" ); document.write( "======================
\n" ); document.write( "Do the others the same way.
\n" ); document.write( "A=(-3,-5)B=(3,-13)\r
\n" ); document.write( "\n" ); document.write( "A=(2,-2)B(-2,2)\r
\n" ); document.write( "\n" ); document.write( "A=(4,-6)B=(-2,4)
\n" ); document.write( "
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