document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59873>Question 59873</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two munbers is 21. Three times the smaller number is two less than twice the larger number. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41091 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=21 SO X=21-Y   AND<BR>\n" );
document.write( "3X=2Y-2<BR>\n" );
document.write( "3(21-Y)=2Y-2<BR>\n" );
document.write( "63-3Y=2Y-2<BR>\n" );
document.write( "-3Y-2Y=-2-63<BR>\n" );
document.write( "-5Y=-65<BR>\n" );
document.write( "Y=-65/-5<BR>\n" );
document.write( "Y=13<BR>\n" );
document.write( "THEN X+13=21<BR>\n" );
document.write( "X=21-13<BR>\n" );
document.write( "X=8<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3*8=2*13-2<BR>\n" );
document.write( "24=26-2<BR>\n" );
document.write( "24=24 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );