document.write( "Question 659758: a Father has two sons. The oldest son is 3 yrs older then the younger son. The father is 6 times older then the oldest son. sum of the ages of the 3 people is 47. Calculate the ages of the 3 individuals
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Algebra.Com's Answer #410908 by ReadingBoosters(3246)\"\" \"About 
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x = father
\n" ); document.write( "y = older son
\n" ); document.write( "z = younger son\r
\n" ); document.write( "\n" ); document.write( "y = 3 + z
\n" ); document.write( "x = 6(y)
\n" ); document.write( "x + y + z = 47\r
\n" ); document.write( "\n" ); document.write( "Plug the first two equations into the third equation
\n" ); document.write( "6y + (3 + z) + z = 47
\n" ); document.write( "6(3+z) + 3 + z + z = 47
\n" ); document.write( "18 + 6z + 3 + z + z = 47
\n" ); document.write( "21 + 8z = 47
\n" ); document.write( "21 - 21 + 8z = 47 - 21
\n" ); document.write( "8z = 26
\n" ); document.write( "8x/8 = 26/8
\n" ); document.write( "z = 3.25 youngest son\r
\n" ); document.write( "\n" ); document.write( "y = 3 + z = 3 + 3.25 = 6.25 oldest son\r
\n" ); document.write( "\n" ); document.write( "x = 6(6.25) = 37.5 father
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