document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659727>Question 659727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One angle is 3 less than four times the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410889 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplementary angles add to 180.  Call the angles x and y.  x+y=180<P><BR>\n" );
document.write( "x = 4y-3 (three less than 4 times y).  Substitute this for x into the first equation and solve it.<P><BR>\n" );
document.write( "4y-3+y = 180<P><BR>\n" );
document.write( "5y = 183<P><BR>\n" );
document.write( "y=36.6<P><BR>\n" );
document.write( "x = 180-36.6 = 143.4 </SPAN>\n" );
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