document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659651>Question 659651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 3 less than twice another.The sum of the two numbers is 51. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410878 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 51<BR>\n" );
document.write( "x = 2y - 3\r<BR>\n" );
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document.write( "Substitute the second equation into the first<BR>\n" );
document.write( "2y - 3 + y = 51<BR>\n" );
document.write( "Combine like terms<BR>\n" );
document.write( "3y - 3 + 3 = 51 + 3<BR>\n" );
document.write( "3y = 54<BR>\n" );
document.write( "3y/3 = 54/3<BR>\n" );
document.write( "y = 18<BR>\n" );
document.write( "Plug y into the second equation to solve for x<BR>\n" );
document.write( "x = 2(18) - 3 = 36 - 3 = 33<BR>\n" );
document.write( "y = 18, x = 33 </SPAN>\n" );
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