document.write( "Question 659584: Helen has a $1.35 in her bank in nickles and dimes. There are 9 more nickles than dimes. Find the number she has of each kind \n" ); document.write( "
Algebra.Com's Answer #410851 by ReadingBoosters(3246) ![]() You can put this solution on YOUR website! x = nickles \n" ); document.write( "y = dimes\r \n" ); document.write( "\n" ); document.write( "$1.35 = .05x + .1y \n" ); document.write( "x = y + 9\r \n" ); document.write( "\n" ); document.write( "Substitute the second equation in the first equation \n" ); document.write( ".05(y+9) + .1y = 1.35 \n" ); document.write( "Distribute the .05 \n" ); document.write( ".05y + .45 + .1y = 1.35 \n" ); document.write( "Combine like terms \n" ); document.write( ".15y + .45 = 1.35 \n" ); document.write( ".15y + .45 - .45 = 1.35 - .45 \n" ); document.write( ".15y = .9 \n" ); document.write( ".15y/.15 = .9/.15 \n" ); document.write( "y = 6 dimes\r \n" ); document.write( "\n" ); document.write( "Plug the y value into the second equation \n" ); document.write( "x = 6 + 9 \n" ); document.write( "x = 15 nickles\r \n" ); document.write( "\n" ); document.write( "Proof \n" ); document.write( "6 dimes = .1(6) = $.60 \n" ); document.write( "15 nickles = .05(15) = $.75 \n" ); document.write( "$.60 + $.75 = $1.35 \n" ); document.write( " |