document.write( "Question 659535: Hello,\r
\n" ); document.write( "\n" ); document.write( "Question: The radiator in a certain make of a car needs to contain 40 liters of 40% antifreeze. The radiator now contains 40 liters of 20% antifreeze. How many liters of this solution must be drained and replaced with 100% antifreeze to get the desired strength?\r
\n" ); document.write( "\n" ); document.write( "I have tried creating a table like my teacher suggested and am having a difficult time with that method. I know that my goal is to set up a system of equations but I never know where to place the variables and which number corresponds to that variable.\r
\n" ); document.write( "\n" ); document.write( "Thanks,
\n" ); document.write( " Katie
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Algebra.Com's Answer #410824 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The actual amount of antifreeze required = \"40%2840%2F100%29+=+16\" liter\r
\n" ); document.write( "\n" ); document.write( "The amount of anti freeze present in \"40\" liters of \"20\"% = \"40%2820%2F100%29+=+8\" liters\r
\n" ); document.write( "\n" ); document.write( "let the amount to be drained be \"x\" liters\r
\n" ); document.write( "\n" ); document.write( "so the amount of antifreeze drained will be \"x%2820%2F100%29+=+0.2+x\"\r
\n" ); document.write( "\n" ); document.write( "amount of antifreeze still present is \"8+-+0.2x\"\r
\n" ); document.write( "\n" ); document.write( "since\"+x\" liters is drained number liters of \"100\"% antifreeze it has \r
\n" ); document.write( "\n" ); document.write( "to be added to present \"8+-+0.2x\"\r
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\n" ); document.write( "\n" ); document.write( "so, we have \"8+-+0.2x+%2B+x+=+16\"\r
\n" ); document.write( "\n" ); document.write( "\"0.8x+=+16-8\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+8%2F0.8\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+10%29\" liters -------answer\r
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