document.write( "Question 659520: Please help me with this question!\r
\n" ); document.write( "\n" ); document.write( "Two cyclists, 48 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 2 hr later, at what average speed is each cyclist traveling?\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #410817 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The easiest way to do this is to imagine that one
\n" ); document.write( "of the cyclists is standing still and the other is
\n" ); document.write( "approaching at the sum of their speeds and will
\n" ); document.write( "cover 48 miles in 2 hrs
\n" ); document.write( "Let \"+s+\" = the speed of the slower cyclist
\n" ); document.write( "\"+2s+\" = the speed of the other cyclist
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\n" ); document.write( "\"+48+=+%28+s+%2B+2s+%29%2A2+\"
\n" ); document.write( "\"+48+=+%283s%29%2A2+\"
\n" ); document.write( "\"+48+=+6s+\"
\n" ); document.write( "\"+s+=+8+\"
\n" ); document.write( "\"+2s+=+16+\"
\n" ); document.write( "Their speeds are 8 mi/hr and 16 mi/hr
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