document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659460>Question 659460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist 80 mil of 25% chemical solution. he only has a 50% chemical solution and a 10% chemical solution. find how many ml of each he should mix to  get the desired solution.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410801 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist 80 mil of 25% chemical solution. he only has a 50% chemical solution and a 10% chemical <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.50x + 0.10(80-x) = 0.25*80<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "50x + 10*80 - 10x = 25*80<BR>\n" );
document.write( "40x = 15*80<BR>\n" );
document.write( "x = 30 ml (amt. of 50% solution needed)<BR>\n" );
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document.write( "80-x = 70 ml (amt. of 10% solution needed)<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );