document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659450>Question 659450</A>: <I><SPAN STYLE=\"word-break: break-all;\">  The given equation is either linear or equivalent to a linear equation. Solve the equation\r<BR>\n" );
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document.write( " 3/4 y + 1/3(y-4)=(y+1)/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410787 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given equation is either linear or equivalent to a linear equation. Solve the equation <BR>\n" );
document.write( "3/4 y + 1/3(y-4)=(y+1)/4<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Multiply thru by 12 to get:<BR>\n" );
document.write( "9y + 4(y-4) = 3(y+1)<BR>\n" );
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document.write( "9y + 4y - 16 = 3y + 3<BR>\n" );
document.write( "10y = 19<BR>\n" );
document.write( "y = 1.9<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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