document.write( "Question 659283: Doug travels 5 times faster than jill. traveling in opposite directions they are 504 miles apart after 4 hours. Find their rates of travel.\r
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Algebra.Com's Answer #410716 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "Doug travels 5 times faster than jill's rate \"highlight%28r%29\"
\n" ); document.write( "jill's rate: r
\n" ); document.write( "Doug's rate: 5r
\n" ); document.write( "traveling in opposite directions they are 504 miles apart after 4 hours
\n" ); document.write( "Note: D = rt
\n" ); document.write( " \"r%2A4hr+%2B+5r%2A4hr+=+504mi\"
\n" ); document.write( " 24r = 504
\n" ); document.write( " r = 21mph, Jill's rate. Doug's rate is 105mph \n" ); document.write( "
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