document.write( "Question 659250: you started on a bike trip, riding at a rate of 9 miles per hour. your friend left one hour later and rode at rate of 12 miles per hour. how long did it take your friend to catch up with you? your distance = your friend's distance. solve for t. t= your time in hours. t+1= friend time in hours \n" ); document.write( "
Algebra.Com's Answer #410705 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Your equation:
\n" ); document.write( "\"+d+=+9t%5B1%5D+\"
\n" ); document.write( "Your friend's equation:
\n" ); document.write( "\"+d+=+12t%5B2%5D+\"
\n" ); document.write( "--------------
\n" ); document.write( "\"+9t%5B1%5D+=+12t%5B2%5D+\"
\n" ); document.write( "\"+t%5B2%5D+=+%283%2F4%29%2At%5B1%5D+\"
\n" ); document.write( "------------------
\n" ); document.write( "This doesn't take into account the extra hour
\n" ); document.write( "which the friend takes, so I add 1 hr to his time
\n" ); document.write( "--------------
\n" ); document.write( "Time to catch up occurs when
\n" ); document.write( "\"+%283%2F4%29%2At%5B1%5D+%2B+1+=+t%5B1%5D+\"
\n" ); document.write( "\"+%281%2F4%29%2At%5B1%5D+=+1+\"
\n" ); document.write( "\"+t%5B1%5D+=+4+\" hrs
\n" ); document.write( "--------------
\n" ); document.write( "The friend catches up in 4 hrs
\n" ); document.write( "check:
\n" ); document.write( "\"+d+=+9t%5B1%5D+\"
\n" ); document.write( "\"+d+=+9%2A4+\"
\n" ); document.write( "\"+d+=+36+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d+=+12t%5B2%5D+\"
\n" ); document.write( "\"+d+=+12%2A%283%2F4%29%2At%5B1%5D+\"
\n" ); document.write( "\"+d+=+9%2At%5B1%5D+\"
\n" ); document.write( "\"+d+=+9%2A4+\"
\n" ); document.write( "\"+d+=+36+\"
\n" ); document.write( "------------
\n" ); document.write( "This is done a little differently than the
\n" ); document.write( "problem expects, but I think it's right.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );