document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59821>Question 59821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i can never figure out word problems can you please help.  thank you in advance\r<BR>\n" );
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document.write( "108. Boxing match.  A boxing ring is in the shape of a square, 20 feet on each side.  How    far apart are the fighters when they are in opposite corners of the ring? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41069 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE DIAGONAL OF A SQUARE 20 FOOT RING IS SOLVED BY THE FORMULA A^2+B^2=C^2 WHERE THE A & B SIDES ARE 20 FEET. THUS THE DIAGONAL (C) IS<BR>\n" );
document.write( "20^2+20^2=C^2<BR>\n" );
document.write( "400+400=C^2<BR>\n" );
document.write( "800=C^2<BR>\n" );
document.write( "C=SQRT800<BR>\n" );
document.write( "C=28.28 FEET IS THE DIAGONAL ACROSS THE RING<BR>\n" );
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