document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659156>Question 659156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem, i can't understand it. One side of a triangle is four less than twice the shortest side. The third side is six more than the shortest side. Find the measure of each side if the perimeter of a triangle is 34 m. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410682 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem, i can't understand it. One side of a triangle is four less than twice the shortest side. The third side is six more than the shortest side. Find the measure of each side if the perimeter of a triangle is 34 m<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=length of shortest side<BR>\n" );
document.write( "2x-4=length of 2nd side<BR>\n" );
document.write( "x+6=length of 3rd side<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+2x-4+x+6=34<BR>\n" );
document.write( "4x+2=34<BR>\n" );
document.write( "4x=32<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "2x-4=12<BR>\n" );
document.write( "x+6=14<BR>\n" );
document.write( "..<BR>\n" );
document.write( "length of shortest side=8 m<BR>\n" );
document.write( "length of 2nd side=12 m<BR>\n" );
document.write( "length of 3rd side=14 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );