document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659127>Question 659127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by factoring and using the principle of zero products....(5x +8)(x + 2)= 29x + 28....I am having a hard time with this and need to see the work...thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410673 by </B><A HREF=/tutors/aboutme.mpl?userid=reviewermath><B>reviewermath(1029)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=reviewermath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=reviewermath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiply the two binomials on the left side of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%5E2+%2B+18x+%2B+16+=+29x+%2B+28 ALIGN=MIDDLE  ALT=\"5x%5E2+%2B+18x+%2B+16+=+29x+%2B+28\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Transpose 29x + 28 to the left side.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5x%5E2+-+11x+-+12+=+0 ALIGN=MIDDLE  ALT=\"5x%5E2+-+11x+-+12+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "factor the left side<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285x+%2B+4%29%28x+-3%29+=+0 ALIGN=MIDDLE  ALT=\"%285x+%2B+4%29%28x+-3%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Equate each factor to zero and solve for x<BR>\n" );
document.write( "Answers: x = -4/5, 3 </SPAN>\n" );
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