document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59822>Question 59822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me with this word problem.  thank you very much\r<BR>\n" );
document.write( "\n" );
document.write( "112. Swimming pool design. An architect has a designed a motel pool with in a rectangular area the is fenced on three sides.  If she uses 60 yards of fencing to enclose as area of 352 square yards, then what are the dimensions for L and W?  Assume L is greater than W </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #41067 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=41067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L*W=352<BR>\n" );
document.write( "2L+W=60<BR>\n" );
document.write( "W=60-2L<BR>\n" );
document.write( "L(60-2L)=352<BR>\n" );
document.write( "60L-2L^2-352=0<BR>\n" );
document.write( "-2L^2+60L-352=0<BR>\n" );
document.write( "L^2-30L+176=0<BR>\n" );
document.write( "(L-22)(L-8)=0<BR>\n" );
document.write( "L-22=0<BR>\n" );
document.write( "L=22 SOLUTION<BR>\n" );
document.write( "L-8=0<BR>\n" );
document.write( "L=8 SOLUTION<BR>\n" );
document.write( "22*W=352<BR>\n" );
document.write( "W=352/22<BR>\n" );
document.write( "W=16 SOLUTION<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "2*22+16=60<BR>\n" );
document.write( "44+16=60<BR>\n" );
document.write( "60=60<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );