document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659100>Question 659100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line through (6,-5) and parallel to 4x-2y+7=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410669 by </B><A HREF=/tutors/aboutme.mpl?userid=nicy12><B>nicy12(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nicy12><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the line through (6,-5) is  parallel to 4x-2y+7=0, they must have same slope.\r<BR>\n" );
document.write( "\n" );
document.write( "solving  for the slop  of 4x-2y+7=0 :\r<BR>\n" );
document.write( "\n" );
document.write( "m= -A/B\r<BR>\n" );
document.write( "\n" );
document.write( "m=-4/-2\r<BR>\n" );
document.write( "\n" );
document.write( "m=2\r<BR>\n" );
document.write( "\n" );
document.write( "------\r<BR>\n" );
document.write( "\n" );
document.write( "using the given point: (6,-5) and the slope 2, we can use the point-slope form for finding the equation.\r<BR>\n" );
document.write( "\n" );
document.write( "(y-y1)=m(x-x1)\r<BR>\n" );
document.write( "\n" );
document.write( "y+5=2(x-6)\r<BR>\n" );
document.write( "\n" );
document.write( "y+5=2x-12\r<BR>\n" );
document.write( "\n" );
document.write( "2x-y-17=0\r<BR>\n" );
document.write( "\n" );
document.write( "the equation  of  a line  through (6,-5) is 2x-y-17=0\r<BR>\n" );
document.write( "\n" );
document.write( "i hope it helped you :) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );