document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=659095>Question 659095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kimberly has $1.95 in dimes and quarters. Find all possibilities for the number of each type of coin she could have. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410652 by </B><A HREF=/tutors/aboutme.mpl?userid=colliefan><B>colliefan(242)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=colliefan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since 1.95 ends in a 5 cent increment, she has to have one quarter or three quarters or 5 quarters or 7 quarters. Eight quarters would be $2.00 and so too many. If she had an even number of quarters, you can't get a total ending in 5 cents. Then, just figure out how many dimes she would need to get to the total.\r<BR>\n" );
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document.write( "1 quarter plus 17 dimes<BR>\n" );
document.write( "3 quarters plus 12 quarters<BR>\n" );
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