document.write( "Question 59808This question is from textbook Alegbra Concepts and Applications
\n" ); document.write( ": Use Elimination to solve\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3%2B4y=30\"\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"2x-y=5\"
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Algebra.Com's Answer #41064 by joyofmath(189)\"\" \"About 
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(1) \"x%2F3%2B4y=30\"
\n" ); document.write( "(2) \"2x-y=5\"\r
\n" ); document.write( "\n" ); document.write( "Add y to both sides of equation (2) to get \"2x=5%2By\"
\n" ); document.write( "Then subtract 5 from both sides and you get \"y=2x-5\"
\n" ); document.write( "Replace y with \"2x-5\" in (1) and you get \r
\n" ); document.write( "\n" ); document.write( "(3) \"x%2F3%2B4%282x-5%29=30\"\r
\n" ); document.write( "\n" ); document.write( "Multiply 4 by 2x-5 to get 8x-20 so (3) becomes\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3%2B8x-20=30\"\r
\n" ); document.write( "\n" ); document.write( "Add 20 to both sides to get \r
\n" ); document.write( "\n" ); document.write( "(4) \"x%2F3%2B8x=50\"\r
\n" ); document.write( "\n" ); document.write( "Add \"x%2F3\" to \"8x\" to get \"%288%2B1%2F3%29x\"
\n" ); document.write( "But, \"8=24%2F3\" so \"%288%2B1%2F3%29x=%2824%2F3%2B1%2F3%29x=%2825%2F3%29x\"\r
\n" ); document.write( "\n" ); document.write( "So, replacing \"x%2F3%2B8x\" with \"%2825%2F3%29x\" in (4) we get
\n" ); document.write( "\"%2825%2F3%29x=50\"\r
\n" ); document.write( "\n" ); document.write( "Now, multiply both sides by \"3%2F25\" and we get \"x=50%283%2F25%29\" or x=6.
\n" ); document.write( "Since x=6, we replace x with 6 in (2) and get \"2%2A6-y=5\" or \"12-y=5\" so y=7.\r
\n" ); document.write( "\n" ); document.write( "To verify that x=6, y=7 is correct we use these values in (1) and (2):\r
\n" ); document.write( "\n" ); document.write( "From (1): \"x%2F3%2B4y=30\" or \"6%2F3%2B4%2A7=2%2B28\" which is indeed 30, and
\n" ); document.write( "From (2): \"2x-y=5\" or \"2%2A6-7=12-7\" which is indeed 5.
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