document.write( "Question 658991: Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to create a 50% solution of sulfuric acid solution? \n" ); document.write( "

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Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to create a 50% solution of sulfuric acid solution?
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\n" ); document.write( "60*0.8 = 48 ml of acid.
\n" ); document.write( "To be 50%, 48 ml of water are needed --> 96 ml of solution.
\n" ); document.write( "96 - 60 = 36 ml of water to add.
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\n" ); document.write( "Or,
\n" ); document.write( "x*0 + 60*80 = (60 + x)*50
\n" ); document.write( "3000 + 50x = 4800
\n" ); document.write( "50x = 1800
\n" ); document.write( "x = 36 ml \n" ); document.write( "

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