document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=658996>Question 658996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A furniture shop refurnishes tables. Employees use 1 of two methods to refinish each table.  Method I takes 1 hour to finish and the material costs $7. method II takes 1.5 hours, and the material costs $6. Next week, they plan to spend 88 hours in labor and $526 in material for refinishing tables. How many tables should they plan to refinish with each method? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410581 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # of tables made with method 1, y = # of tables made with method 2\r<BR>\n" );
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document.write( "Hours:\r<BR>\n" );
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document.write( "1x+1.5y = 88\r<BR>\n" );
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document.write( "x = 88 - 1.5y\r<BR>\n" );
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document.write( "Cost:\r<BR>\n" );
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document.write( "7x+6y = 526\r<BR>\n" );
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document.write( "7(88 - 1.5y)+6y = 526\r<BR>\n" );
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document.write( "7(88-15y)+6y=526\r<BR>\n" );
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document.write( "616-10.5y+6y=526\r<BR>\n" );
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document.write( "-4.5y+616=526\r<BR>\n" );
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document.write( "-4.5y=526-616\r<BR>\n" );
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document.write( "-4.5y=-90\r<BR>\n" );
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document.write( "y=(-90)/(-4.5)\r<BR>\n" );
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document.write( "y=20\r<BR>\n" );
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document.write( "x = 88 - 1.5y\r<BR>\n" );
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document.write( "x = 88 - 1.5(20)\r<BR>\n" );
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document.write( "x = 58\r<BR>\n" );
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document.write( "So you should make 58 tables using method 1 and 20 tables using method 2 </SPAN>\n" );
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