document.write( "Question 658963: One side of a triangle is half the longest side.the third side is 12 ft less then the longest side. The perimeter is 53 ft. Find all three sides. \n" ); document.write( "
Algebra.Com's Answer #410570 by DrBeeee(684)\"\" \"About 
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Let c = the longest side
\n" ); document.write( "Let a = one side
\n" ); document.write( "Let b = the other side
\n" ); document.write( "The perimeter, p, is given by
\n" ); document.write( "(1) p = a + b + c
\n" ); document.write( "From the problem statement we have
\n" ); document.write( "(2) a = c/2 and
\n" ); document.write( "(3) b = c - 12
\n" ); document.write( "Substitute (2) and (3) into (1) and get
\n" ); document.write( "(4) p = c/2 + c - 12 + c or
\n" ); document.write( "(5) p = (5/2)c - 12
\n" ); document.write( "Using the given value of p yields
\n" ); document.write( "(6) (5/2)c - 12 = 53 or
\n" ); document.write( "(7) (5/2)c = 65 or
\n" ); document.write( "(8) 5c = 130 or
\n" ); document.write( "(9) c = 26
\n" ); document.write( "Then
\n" ); document.write( "a = 13 and b = 14.
\n" ); document.write( "Let's check these values.
\n" ); document.write( "Is (26+13+14 = 53)?
\n" ); document.write( "Is (53 = 53)? Yes
\n" ); document.write( "Answer: The three sides of the triangle are 26, 13 and 14 units in lenght.\r
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