document.write( "Question 658944: What is the equation of a line that contains the point (0,4) and is perpendicular to the line y-8=3(x-5) \n" ); document.write( "

Algebra.Com's Answer #410556 by jim_thompson5910(35256) $\"\"$ $\"About$

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The slope of y-8=3(x-5) is 3.\r
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\n" ); document.write( "\n" ); document.write( "Rewrite 3 as 3/1. Then flip the fraction and flip the sign to get -1/3\r
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\n" ); document.write( "\n" ); document.write( "So the perpendicular slope is m = -1/3\r
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\n" ); document.write( "\n" ); document.write( "Use this (m = -1/3) and the given point (0,4) and plug them into y = mx+b to get\r
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\n" ); document.write( "\n" ); document.write( "y = mx + b\r
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\n" ); document.write( "\n" ); document.write( "4 = (-1/3)(0) + b\r
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\n" ); document.write( "\n" ); document.write( "Now solve for b\r
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\n" ); document.write( "\n" ); document.write( "4 = 0 + b\r
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\n" ); document.write( "\n" ); document.write( "4 = b\r
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\n" ); document.write( "\n" ); document.write( "b = 4\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the perpendicular line is $\"x\"$ \n" ); document.write( "

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