document.write( "Question 658889: knowing that log10((x+y)/3)=1/2(log10(x)+log10(y)) determine the value for x/y\r
\n" ); document.write( "\n" ); document.write( "P.S - the 3 is inside the log and the log base is 10.
\n" ); document.write( "

Algebra.Com's Answer #410542 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"++log%28+%28x%2By%29%2F3+%29+=+%281%2F2%29%2A%28+log%28x%29+%2B+log%28y%29+%29+\"
\n" ); document.write( "\"++log%28+%28x%2By%29%2F3+%29+=+%281%2F2%29%2A%28+log%28x%2Ay%29+%29+\"
\n" ); document.write( "\"++log%28+%28x%2By%29%2F3+%29+=++log%28sqrt%28x%2Ay%29%29++\"
\n" ); document.write( "\"+%28+x+%2B+y+%29+%2F+3+=+sqrt%28+x%2Ay+%29+\"
\n" ); document.write( "Square both sides
\n" ); document.write( "\"+%28+x+%2B+y+%29%5E2+%2F+9+=+x%2Ay+\"
\n" ); document.write( "\"++x%5E2+%2B+2x%2Ay+%2B+y%5E2++=+9x%2Ay+\"
\n" ); document.write( "\"+x%5E2+%2B+y%5E2+=+7x%2Ay+\"
\n" ); document.write( "Divide both sides by \"+y%5E2+\"
\n" ); document.write( "\"++%28x%2Fy%29%5E2+%2B+1++=+7%2A%28x%2Fy%29+\"
\n" ); document.write( "Solve for \"+x%2Fy+\" Have to run.
\n" ); document.write( "Hope I got it.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );