document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=658778>Question 658778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rate 1 $42 plus $.12 mile<BR>\n" );
document.write( "Rate 2 $84 plus .06 mile<BR>\n" );
document.write( "How many miles must one drive to pay less than Rate 2\r<BR>\n" );
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document.write( "how do I work this problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410527 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> plan a = 42 + .12*x<BR>\n" );
document.write( "plan b = 84 + .06*x<BR>\n" );
document.write( "x represents the number of miles driven.\r<BR>\n" );
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document.write( "you want to find the number of miles that has to be driven in order for r.1 to be less than r.2\r<BR>\n" );
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document.write( "set your equation as:\r<BR>\n" );
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document.write( "cost for plan a < cost for plan b\r<BR>\n" );
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document.write( "since cost for plan a = 42 + .12*x and cost for plan b = 84 + .06*x, your equation becomes:\r<BR>\n" );
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document.write( "42 + .12*x < 84 + .06*x\r<BR>\n" );
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document.write( "you want to solve for x.\r<BR>\n" );
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document.write( "subtract 42 from both sides of the equation to get:\r<BR>\n" );
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document.write( ".12*x < 84 + .06*x - 42\r<BR>\n" );
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document.write( "subtract .06*x from both sides of the equation to get:\r<BR>\n" );
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document.write( ".12*x - .06*x < 84 - 42\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( ".06*x < 42\r<BR>\n" );
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document.write( "divide both sides of the equation by .06 to get:\r<BR>\n" );
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document.write( "x < 42 / .06 which becomes x < 700\r<BR>\n" );
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document.write( "if the number of miles driven is less than 700 then cost for plan a will be less than cost for plan b\r<BR>\n" );
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document.write( "if the number of miles driven is equal to or greater than 700 then cost for plan a will be greater than or equal to cost for plan b\r<BR>\n" );
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document.write( "the following table shows the number of miles driven and the cost for plan a compared to the cost for plan b.\r<BR>\n" );
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document.write( "number of miles driven\r\n" );
document.write( "        cost for plan a\r\n" );
document.write( "                     cost for plan b\r\n" );
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document.write( "699	125.88	     125.94\r\n" );
document.write( "700	126	     126\r\n" );
document.write( "701	126.12	     126.06\r\n" );
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document.write( "at 699 miles, plan a costs less than plan b<BR>\n" );
document.write( "at 700 miles, plan a and plan b cost the same.<BR>\n" );
document.write( "at 701 miles, plan a is more expensive than plan b.\r<BR>\n" );
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document.write( "if the miles driven are less than 700, plan a will always cost less than plan b.\r<BR>\n" );
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document.write( "if the miles driven are greater than 700, plan a will always cost more than plan b.\r<BR>\n" );
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document.write( "you may substitute different miles to confirm for yourself that this is accurate.<BR>\n" );
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