document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=658837>Question 658837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer can plow the field in 8 days. After working 3 days, his son joins him and together they plow the field in 3 more days. How many days will it require for the son to plow the field alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410514 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A farmer can plow the field in 8 days. After working 3 days, his son joins him and together they plow the field in 3 more days. How many days will it require for the son to plow the field alone?<BR>\n" );
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document.write( "Let x = days for son to plow alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3(1/8) + 3(1/x + 1/8) = 1<BR>\n" );
document.write( "3/8 + 3/x + 3/8 = 1<BR>\n" );
document.write( "multiply both sides by 8x:<BR>\n" );
document.write( "3x + 24 + 3x = 8x<BR>\n" );
document.write( "6x + 24 = 8x<BR>\n" );
document.write( "24 = 2x<BR>\n" );
document.write( "12 days = x  (answer)<BR>\n" );
document.write( " </SPAN>\n" );
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