document.write( "Question 658764: tanx/secx-1 - sinx /1+cosx = 2 cotx \n" ); document.write( "
Algebra.Com's Answer #410480 by lwsshak3(11628)\"\" \"About 
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tanx/secx-1 - sinx /1+cosx = 2 cotx
\n" ); document.write( "start with left side
\n" ); document.write( "tan/sec-1-sin/1+cos
\n" ); document.write( "(sin/cos)/[(1/cos)-1]-[sin/(1+cos)]
\n" ); document.write( "=(sin/cos)/[(1-cos)/cos]-[sin/(1+cos)]
\n" ); document.write( "=[(sin/(1-cos)]-[sin/(1+cos)]
\n" ); document.write( "LCD: (1-cos)(1+cos)
\n" ); document.write( "=[sin(1+cos)-sin(1-cos)]/(1-cos)(1+cos)
\n" ); document.write( "=[sin(1+cos)-sin(1-cos)]/(1-cos^2)
\n" ); document.write( "=[sin(1+cos)-sin(1-cos)]/(sin^2)
\n" ); document.write( "divide by sin
\n" ); document.write( "=[1+cos-1+cos)]/(sin)
\n" ); document.write( "=2cos/sin
\n" ); document.write( "=2 cotx
\n" ); document.write( "verified: left side=right side \n" ); document.write( "
\n" );