document.write( "Question 658775: The sum of the digits of a two digit number is 9. Also, nine times this number is twice the number obtained by reversing the digits of the number. Find the number. \n" ); document.write( "
Algebra.Com's Answer #410478 by lwsshak3(11628)\"\" \"About 
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The sum of the digits of a two digit number is 9. Also, nine times this number is twice the number obtained by reversing the digits of the number. Find the number.
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\n" ); document.write( "let u=units digit
\n" ); document.write( "let t=tens digit
\n" ); document.write( "t+u=9
\n" ); document.write( "t=9-u
\n" ); document.write( "number=10t+u
\n" ); document.write( "..
\n" ); document.write( "9(10t+u)=2(10u+t)
\n" ); document.write( "90t+9u=20u+2t
\n" ); document.write( "11u=88t=88(9-u)=792-88u
\n" ); document.write( "99u=792
\n" ); document.write( "u=792/99
\n" ); document.write( "u=8
\n" ); document.write( "t=9-u=1
\n" ); document.write( "10t+u=10+8=18
\n" ); document.write( "number=18
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