document.write( "Question 203260: A solution of salt and water contains 18 ounces of pure salt and 36 ounces of water. How many ounces of water must be added to obtain a 24% pure salt solution?\r
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document.write( "I have tried many different solutions and I feel there is something more needed on the right hand side of the equation, but I can't figure it out.\r
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document.write( "1) x+36
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document.write( " ---- = 24%
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document.write( " x+54\r
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document.write( "2) x+18
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document.write( " ---- = 24%
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document.write( " x+24 \n" );
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Algebra.Com's Answer #410415 by NaturalBornNerd(5)![]() ![]() You can put this solution on YOUR website! I approached the problem in a different way and got a different answer, \n" ); document.write( "but it seems to check out. \n" ); document.write( "First,18oz. of salt in 36oz. of water is a 50% solution. \n" ); document.write( "I don't think we need to be concerned with the amount of salt as a variable, \n" ); document.write( "but only the amount of water we need to dilute our mixture down to a 24% concentration of salt. \n" ); document.write( "If we let 'w' = water, then what we have is 18/36w = 0.05 (oop's, this is a typo. I mean 0.50) . \n" ); document.write( "What we want is 18/w = 0.24, so... \n" ); document.write( " 18/w = 0.24\r \n" ); document.write( "\n" ); document.write( " 18 = 0.24w\r \n" ); document.write( "\n" ); document.write( " 18/0.24 = w\r \n" ); document.write( "\n" ); document.write( " w = 75. So we need to have 18oz. of salt in 75 ounces of water to have a 24% solution.\r \n" ); document.write( "\n" ); document.write( "To achieve this , we need to add 75oz. - 36oz. = 39oz. of water to our original mixture.\r \n" ); document.write( "\n" ); document.write( "We check our answer by dividing 18oz.(salt)/75oz.(water)= 24%(salt). \n" ); document.write( " \n" ); document.write( " |