document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=658689>Question 658689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this: 7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power.  I know the answer is 1, but do not know how to get<BR>\n" );
document.write( "to that answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410406 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410406\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (7^-4)^-2 = 7^(-4*-2) = 7^8\r<BR>\n" );
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document.write( "(7^4)^-2 = 7^(4*-2) = 7^-8\r<BR>\n" );
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document.write( "So \"7 to the negative 4th to the negative 2 power times 7 to the 4th to the negative 2 power\" becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=7%5E8%2A7%5E%28-8%29+=+7%5E%288%2B%28-8%29%29+=+7%5E0+=+1 ALIGN=MIDDLE  ALT=\"7%5E8%2A7%5E%28-8%29+=+7%5E%288%2B%28-8%29%29+=+7%5E0+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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