document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=658610>Question 658610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An isosceles right triangle has legs measuring (x + 1) cm each. The hypotenuse has measure (x + 5) cm.  Find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #410341 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=410341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An isosceles right triangle has legs measuring (x + 1) cm each. The hypotenuse has measure (x + 5) cm. Find x.<BR>\n" );
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document.write( "Use Pythagoras:<BR>\n" );
document.write( "2(x+1)^2 = (x+5)^2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "2[x^2 + 2x + 1] = x^2 + 10x + 25<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x^2 + 4x + 2 = x^2 + 10x + 25<BR>\n" );
document.write( "x^2 -6x -23 = 0<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = [6 +- sqrt(36 - 4*-23)]/2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = [6 +- sqrt(128)]/2<BR>\n" );
document.write( "x = [6 +- 8sqrt(2)]/2<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 3 + 4sqrt(2)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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